✔ 最佳答案
Use prime factorization:
98 = 2*7*7
28 = 2*2*7
In order to get a number that is divisible by BOTH 98 and 28, you need:
two 2's and two 7's
2*2*7*7 = 196
It is the smallest number that can be divided exactly (without remainder) by 98 and by 28.
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If you were looking for the least common divisor, you would use what is common for both numbers:
one 2 and one 7
2*7 = 14
This is the biggest number that can divide both 98 and 28.