easy方程一問

2B+12=80
2B+12=80
__ __
2 2
B+12-12=80-12
B=68


設乙是Ｂ
3B+B=64
4B=64
__ __
4 4
B=18

1. let b has x dollar, a has (x+12) dollar
x + (x+12) = 80
2x + 12 = 80
2x = 80 - 12
2x = 68
x = 34
b has $34.

2. let 乙 be y, 甲 be 3y
y + 3y = 64
4y = 64
y = 16
乙數是 16.

(易，用於小學)
1.a和b共有80元,a比b多12元,問b有多少元?
(中)
設b有x元
x+x+12=80
x+x =68
2x=68
x=34
b有34元
(英)
let b has x dollar, a has (x+12) dollar
x + (x+12) = 80
2x + 12 = 80
2x = 80 - 12
2x = 68
x = 34
therefore, b has $34.

2.甲,乙兩數的和是64,甲系乙的3倍,問乙數是多少?
(中)
設乙數是y
3y+y=64
4y=64
y=16
乙數是16
(英)
2. let 乙 be y, 甲 be 3y
y + 3y = 64
4y = 64
y = 16
therefore, 乙數是 16.


(難，可用於中學/小學六和五年級)
1.a和b共有80元,a比b多12元,問b有多少元?
a+b=80
a-b=12
a+b+a-b=92
2a=92
2a/2=92/2
a=46
b=34
therefore, b has $34.

2.甲,乙兩數的和是64,甲系乙的3倍,問乙數是多少?
甲為a，乙為b。
a+b=64
a=3b
3b+b=64
4b=64
4b/4=64/4
b=16
a=48
therefore, b is 16.

1.a和b共有80元,a比b多12元,問b有多少元?
a+b=80
a-b=12
a+b+a-b=92
2a=92
2a/2=92/2
a=46
b=34

2.甲,乙兩數的和是64,甲系乙的3倍,問乙數是多少?
甲為a，乙為b。
a+b=64
a=3b
3b+b=64
4b=64
4b/4=64/4
b=16
a=48

1. a+b=80--------(1)
a-b=12--------(2)
(1)-(2)
80-12 = a+b-a+b
68 = 2b
b = 34
2. 甲+乙=64--------(1)
甲=3乙-------(2)
代(2)入(1)
3乙+乙 = 64
乙 = 16

1.a和b共有80元,a比b多12元,問b有多少元?

設b有x元

　　　x+x+12=80
x+x =68
2x=68
x=34
b有34元

2.甲,乙兩數的和是64,甲系乙的3倍,問乙數是多少?

設乙數是y

　　3y+y=64
4y=64
y=16

乙數是16

1. let b has x dollar, a has (x+12) dollar
x + (x+12) = 80
2x + 12 = 80
2x = 80 - 12
2x = 68
x = 34
therefore, b has $34.

2. let 乙 be y, 甲 be 3y
y + 3y = 64
4y = 64
y = 16
therefore, 乙數是 16.