中4數學.唔該大家列詳細步驟啊.唔該大家
1. (x- 2/x )^2 + (x- 2/x ) -2 = 0
2. (x^2 - 2x)^2 - 2x^2+4x-3=0
回答 (2)
1. ( x- 2/x +2)(x-2/x-1)=0
x-2/x = -2 or 1
x2-2=-2x or x
x2+2x-2=0 (rej.)(delta<0) or x2-x-2=0
(x-2)(x+1)=0
x=2 or -1
2. x4-4x3+4x2-2x2+4x-3=0
x4-4x3+2x2+4x-3=0
(x-1)(x3-3x2-x+3)=0
(x-1)2(x2-2x-3)=0
(x+1)(x-3)(x-1)(x-1)=0
x= -1 or 1 or 1 or 3
x= -1 or 1 or 3
1. (x- 2/x )^2 + (x- 2/x ) -2 = 0
Let y=x- 2/x
y^2 + y - 2 = 0
(y+2)(y-1) = 0
y = -2 or 1
x - 2/x = -2 or x - 2/x = 1
x^2 + 2x - 2 = 0 or x^2 - x - 2 = 0
x = [-2+/-sqrt(4+8)]/2 = -1+/-sqrt(3) or (x-2)(x+1)=0 ==> x = 2 or -1
2. (x^2 - 2x)^2 - 2x^2 + 4x - 3 = 0
(x^2 - 2x)^2 - 2(x^2 - 2x) - 3 = 0
Let y = x^2 - 2x
y^2 - 2y - 3 = 0
(y-3)(y+1)=0
y = 3 or -1
x^2 - 2x = 3 or x^2 - 2x = -1
x^2 - 2x - 3 = 0 or x^2 - 2x + 1 = 0
(x-3)(x+1) = 0 or (x-1)^2 = 0
x= 3 or -1 or 1
收錄日期: 2021-04-13 15:33:51
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