1. cos(40°-3﹫)=sin(7﹫+2°)
2. cos37°sin53°+cos53°sin37°
3. (sin19°tan71°-cos19°)2次
4. (cos﹫+1)(cos﹫-1)≡﹣sin﹫cos﹫tan﹫
5. cos(90°-A)分之cos2次A≡sin(90°-A)tan(90°-A)
6.Given that sin﹫=25分之7,find the value of 3tan﹫-cos﹫分之1by using Pythagoras' theorem.
﹫=theta