∫0∞ rk/(1 + r)n dr = ∫0∞ r(n-2-k)/(1 + r)n dr
where k > -1, 1 + k < n
更新1:
∫ r^k/(1 + r)^n dr = ∫r^(n-2-k)/(1 + r)^n dr Integration from 0 to ∞
更新2:
k 同 n 唔一定係 integer
Integration 挑戰
回答 (1)
2008-05-13 10:30 pm
✔ 最佳答案
Substitute r = 1/xRefer to:
http://upload.ysk.hk/photo-175356.html
http://upload.ysk.hk/index-download-175359.html
收錄日期: 2021-04-21 00:29:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080513000051KK00705