Slove 3(5x-2)<x+8?

2008-05-12 3:19 pm
Slove The Inequality.

回答 (10)

2008-05-12 3:26 pm
✔ 最佳答案
3(5x-2)<x+8
15x - 6 < x +8
14x < 14
x < 1
2008-05-12 3:23 pm
3(5x-2)<x+8
15x - 6 < x + 8
14x - 6 < 8
14x < 14
x < 14/14
x < 1
2008-05-12 3:24 pm
3(5x - 2) < x + 8

Expand the brackets:

15x - 6 < x + 8

Add on 6

15x < x + 14

Subtract x

14x < 14

Divide by 14

x < 14/14

x < 1
2008-05-12 3:24 pm
15x-6 < x+8
15x < x +14
14x < 14
x < 1
2016-10-11 6:46 pm
divide each thing through the denominator that's 8 for removing the denominator and then it is going to come out like this: X+40 8=sixty 4 then discover out the linked fee of x: x=sixty 4-40 8 and the linked fee of x=sixteen. ;)
2008-05-12 7:21 pm
15x - 6 < x + 8
14x < 14
x < 1
2008-05-12 4:00 pm
hi there,

first open up the paranthesis on the left side

3(5x-2) = 15x - 6
now you have

15x - 6 < x + 8
put the terms with x on the left hand side and number on the righthand side and have

15x - x < 8 + 6
14x < 14
x < 1
The answer: x < 1
2008-05-12 3:38 pm
3(5x - 2) < x + 8
3*5x - 3*2 < x + 8
15x - 6 < x + 8
15x - x < 6 + 8
14x < 14
x < 14/14
x < 1
2008-05-12 3:37 pm
3(5x-2)<x+8
15x - 6 < x + 8
15x - x< 8 + 6
14x < 14
x < 1
x {...., -3, -2, -1, 0}

^__^ glad to help!
2008-05-12 3:23 pm
14x-<10
x< 5/7


收錄日期: 2021-05-01 10:29:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080512071954AA0n7Ln

檢視 Wayback Machine 備份