(30分) 有關HEAT 唔同物質撈埋

physics8801 錯了

【1kg 既 冰 (0度c) + 1kg 既水蒸氣(100度c) 唔知會變成D乜呢】
絕對要睇呢舊冰同呢堆steam放係咩環境度！

physics8801 的計算只在當【1kg 既 冰 (0度c) + 1kg 既水蒸氣(100度c) 】被放在close system 內才會有可能正確

其他要考慮的因素還有pressure，因為會影嚮到saturation temperature(即boiling point)！
若然saturation temperature低於100度，咁結果液態水0既重量會相對減少，而氣態水0既重量則會相對增加。

physics8801 的計算很好，卻漏了一堆很重要的assumptions.

It will be a mixture of boiling water and steam.

The heat required to melt the 1 kg ice and then raised its temperature to 100 deg.C = (1 x 334000 + 1 x 4200 x 100) J
= 754 000 J
[where 334000 J/kg is the latnet heat of fusion of ice, and 4200 J/kg-C is the specific heat capacity of water]

The mass of steam that needs to be condensed
= 754000/2260000 kg
= 0.334 kg
(where 2260 000 J/kg is the latnet heat of vaporization of water)

Thus, the final mixture contains 1.334 kg of water at 100 deg.C in equilibrium with 0.666 kg of steam at 100 deg.C