數學問題,help!!! +20

2008-05-12 2:28 pm
對錯題,並改正答案:
a) 開方根4+開方根5 = 開方根9 = 3?
b) 5開方根3 = 開方根75
c)開方根6 / 開方根3 = 2
d) 1/開方根2 =開方根2/2

simplify each expression by looking for factors that make ONE.

a) (x+2)(x+2) / (x-3)(x+2)
b) x^2+4x / 2x+8

for the points(-2,1) and (-4,4), find:
a) the distance between the two points.
b) the slope of the line containing the two points.
c) an equation of the line containing the two points.

1.find the slope of the line containing the points (-1,3) and (4,6).
2.find the distance between the points (-1,3) and (4,6)
3.find another point on the line containing the points(-1,3)and(4,6) that has integer coordinates. Write the coordinates of the point you found.
4.Write an equation for the line containing the points(-1,3) and (4,6).

回答 (3)

2008-05-12 5:56 pm
✔ 最佳答案
對錯:
a)錯
兩開方數相加並不是將裡面的數相加
而係如果這兩開方數裡面的數係一樣ge話
就將呢兩個開方數前的係數相加
例如,開方2+開方2,在這裡
這兩個開方數裡面的數都係2
所以這兩個開方數就能加起來
答案就係2開方2
而開方4+開方5係無得相加的
答案就係開方4+開方5

b)對
因為開方75可以睇成開方(5*5*3)
係呢度,5可以開出黎
所以5開方3=開方75

c)錯
開方6/開方3可睇成開方(6/3)
分子分母約左之係
答案係開方2才對

d)對
因為1/開方2的分母有根號
所以要進行分母有理化
分子分母同時乘開方2
所以分母就變成開方2乘開方2
得出分母係2
而分子就只係得開方2
所以答案係開方2/2

2008-05-12 10:04:22 補充:
simplify:
a)(x+2)(x+2) / (x-3)(x+2)
分子分母都有(x+2),所以將佢約左去
最後答案就係(x+2) / (x-3)

b)
x^2+4x / 2x+8
=(x^2+4x+4-4)/2(x+4)
=((x+2)^2-4)/2(x+4)...........完全平方和公式(a^2+2ab+b^2)=(a+b)^2
=(x+2+2)(x+2-2)/2(x+4).....平方差公式a^2-b^2=(a+b)(a-b)
=x/2


=(x+4)x/2(x+4)

2008-05-12 10:05:44 補充:
b)
x^2+4x / 2x+8
=(x^2+4x+4-4)/2(x+4)
=((x+2)^2-4)/2(x+4)....完全平方和公式(a^2+2ab+b^2)=(a+b)^2
=(x+2+2)(x+2-2)/2(x+4)..平方差公式a^2-b^2=(a+b)(a-b)
=(x+4)x/2(x+4)
=x/2

2008-05-12 10:19:00 補充:
point(-2,1) and (-4,4)
a)兩點間距離公式
開方(兩x之差的平方+兩y之差的平方)
即開方((-2+4)^2+(1-4)^2)=開方13

b)slope
=y之差/x之差
=(1-4)/(-2+4)
=-3/2

c)因為而家已兩點同slope
所以可以用點斜式或兩點式求直線方程
點斜式
(y-1)=(-3/2)(x+2)
y-1=(-3/2)x-3
y=(-3/2)x-2

2008-05-12 10:29:30 補充:
1.slope
=(3-6)/(-1-4)
=3/5

2.兩點間距離
=開方((-1-4)^2+(3-6)^2)
=開方34

3.

4.點斜式
y-3=(3/5)(x+1)
y-3=(3/5)x+(3/5)
y=(3/5)x+(18/5)
參考: 自己, 自己, 自己, me, me
2008-05-12 4:43 pm
You've take perfect.
2008-05-12 2:35 pm
all of them are correct
參考: me


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