4z + 12 = 7z - 9 thx! please show the process.?

Hi,

For this question, you first need to subtract 4z from both sides of the equation to get:

12 = 3z - 9

Now, at this point, we need to add 9 to both sides of the equation to get:

21 = 3z

Finally, we need to isolate for z alone by dividing both sides of the equation by 3 as this will undo the operation of multiplication to get:

z = 7 <=== FINAL ANSWER

I hope that helps you out! Please let me know if you have any other questions!

7 - 4 = 3
3z=21
21 divided by 3= 7
z=7
xxxxxxx

21 = 3z
z = 7

Subtact 4z from both sides. 12 = 3z - 9. Add 9 to both sides. 21 = 3z. Divide by 3.
7 = z.

z = 7.

4z + 12 = 7z - 9
+9 +9
4z + 21 = 7z
- 4z -4z
21 = 3z
7 = z

4z + 12 = 7z-9
4z -7z +12 = 7z-7z -9
-3z + 12 - 12 = -9 - 12
-3z/-3 = -21/-3
z = 7

4z + 12 = 7z - 9
4z - 7z = -12 - 9
-3z = -21
z = -21/-3
z = 21/3
z = 7

4z + 12 = 7z - 9
3z = 21
z = 7

7z - 4z=12+9
3z=21
z=7