Factorising (I CANT DO IT!)?

2008-05-11 10:26 am
I am hopeless at factorising and it came up on my test today. I think i got it wrong.... the question was 17 x 9 - 17 x 8

回答 (11)

2008-05-11 10:31 am
✔ 最佳答案
You CAN do it! Think positively!

Notice that both these terms contain a common factor of 17. So,

17 x 9 - 17 x 8 =

17 x (9 - 8) =

17 x 1 =

17
2008-05-11 10:48 am
17 x 9 - 17 x 8
= 17 x (9 - 8)
= 17 x 1
= 17
2008-05-11 10:44 am
Yes you can !
If question is :-
17x^9 - 17x^8
17x^8 (x - 1)

If question is :-
(17 x 9) - (17 x 8)
17 (9 - 8)
17
2008-05-11 10:38 am
17x9-17x8
=17(9-8)
=17x1
=17
question may be wrong or "x" may not be multiplication factor and it may be x as in letters and with power of 9 and 8,then the expression is
17x^9-17x^8
=17x^8(x-1) is the ans
2008-05-11 10:36 am
take 17 as common factor :
17(9-8)=
17(1)=
17
2008-05-11 10:29 am
take 17 as common u will get

17 (9-8) = 17 (1) = 17 dats alllllllllll i don really understand waht u mean by factorising
2008-05-11 10:29 am
17x(9-8)=17
2008-05-11 10:29 am
17(9-8)
17
2008-05-11 10:52 am
17 x 9 - 17 x 8
take 17 as common
17(9 - 8)
17(1)
17-------------------------------is the answer
2008-05-11 10:49 am
Use BODMAS method. So according to BODMAS, the equation becomes:
(17 x 9) - (17 x 8). Since 17 is common, take that out. By doing so, you'll get:
17(9-8), which equals = 17.


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