附加數長題目,圓

2008-05-11 9:53 pm
Question : http://i150.photobucket.com/albums/s87/mllokloks/2002.jpg
Solution : http://i150.photobucket.com/albums/s87/mllokloks/2002_solution.jpg

只係想問b(ii),點解h=2 , k=3 ?
更新1:

| h - k + 3 / 2^05 | = | h + k - 7 / 2^05 | 點解計出黎會唔一樣 ?

回答 (1)

2008-05-11 10:13 pm
✔ 最佳答案
Solving the equations (1) and (2),
h-k+1=0----->h=k-1---------(3)
h+k-5=0-----(2)
put (3) into (2)
k-1+k-5=0
2k=6
k=3 and h=3-1=2


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