Need help solving simultaneous equation system?

y= 2x-1
y= -3x+2
=>
2x-1 = -3x+2
2x+3x = 2+1
5x = 3
x = 3/5

putting in first equation:
y = 2x-1
y = 2(3/5)-1
y = 6/5-1
y = (6-5)/5
y = 1/5

therefore x = 3/5 and y = 1/5 are the required results.

Hope to answer you well. Bye.

x+y = 3----------------------------------one million one million/x +one million/y = one million/ninety------------------------2 using eq one million x= 3-y put in eq 2 one million/ 3-y + one million/y =one million/ ninety y+3-y one million --------- = --------- (3-y)(y) ninety 3 = one million ------------ ----- 3y- y^2 ninety 270 = 3y - 3y^2 0 = 3y^2 - 3y -270 3y^2 - 3y -270 = 0 3 ( y^2 - y -ninety) = 0 y^2 - y -ninety = 0 y^2 +10y - 9y -ninety = 0 y(y+10) - 9 ( y + 10) = 0 (y-9) (y+10) = 0 y= 9 , y= -10 x+y= 3 x+y= 3 x+ 9 = 3 x - 10 = 3 x= -6 x= 13 x= -6 x= 13 y = 9 y= -10

y = 2x - 1

y = -3x + 2
2x - 1 = -3x + 2
2x + 3x = 1 + 2
5x = 3
x = 3/5 (0.6)

y = 2x - 1
y = 2(0.6) - 1
y = 1.2 - 1
y = 0.2 (1/5)

∴ x = 3/5 (0.6) , y = 0.2 (1/5)

For X:
2x-1 = -3x+2

2x-3 = -3x

-3 = -5x

x= 3/5

For Y:
y=3/5 x 2 - 1.
y=6/5-1
y=1/5.

2x - 1 = - 3x + 2
5x = 3
x = 3/5

y = 6/5 - 1
y = 1/5

x = 3/5 , y = 1/5