help! how do i factor these completley?

y² + 2y - 35...
a b c

It will go into the form (y +/- ...) (y +/- ...)
They have to Add together to make b, which is 2.
And they have to multiply together to make c, -35.

(y - 5) (y+7)
Expand out = y² + 7y - 5y - 35
= y² + 2y - 35

n² - 26n + 169
(n - 13) (n - 13)

a² - 15ab + 44b²
(a - 11b) (a- 4b)

8a² - 14a - 15
(2a - 5) (4a + 3)

4c² - 25c + 7
(i dont know!)

hope i helped a little... =S

okkay
everyone else is corrct
except the answer for the last one is
PRIME
when it can be factored its called prime(:

(y + 7)(y - 5)

(n - 13)²

(a - 11b)(a - 4b)

(4a + 3)(2a - 5)

4c² - 25c + 7 ??????

1.y^2+7y-5y-35
=y(y+7)-5(y+7)
=(y-5)(y+7)

2.split middle term into-13 and -13
3.split into -11 and -4
4.split into -20 and -6
5.this is immpossible to split use c=-b+-rtD
2a

(y-7)(y+5)
(a-4b)(a-11b)
(n-13)(n-13)
(4a+3)(2a-5)

The fifth cannot be factored

(y + 7) (y - 5)

(n - 13) (n - 13)

(a - 11) (a - 4)

(y+7)(y-5)
(n-13)^2

1)
y^2 + 2y - 35
= (y + 7)(y - 5)

2)
n^2 - 26n + 169
= (n - 13)(n - 13)
= (n - 13)^2

3)
a^2 - 15ab + 44b^2
= (a - 11b)(a - 4b)

4)
8a^2 - 14a - 15
= (2a - 5)(4a + 3)

5)
4c^2 - 25c + 7
= cannot be factored