How do you find x, when (4x+2)(x-3)=0 ?

If a b = 0
a = 0 or b = 0

(4x + 2)(x - 3) = 0
4x + 2 = 0 , x - 3 = 0
x = - 1/2 , x = 3

(4x + 2)(x - 3) = 0

4x + 2 = 0
4x = -2
x = -2/4
x = -1/2 (-0.5)

x - 3 = 0
x = 3

∴ x = -1/2 (-0.5) , 3

You want to make either of the paraphases 0.
so, if x is -1/2, (4x+2) equals 0 after plugging in x = -1/2
Or x = 3, (x-3) equals 0 after plugging in x= 3
Thus, (4x + 2)(x - 3) = 0 by plugging in either x=3 or -1/2

(4x + 2) = 0 OR (x - 3) = 0
thus
x = -2/4 OR x = -3