(x+y)(x-y) whts the answer?

x^2 -xy +xy -y^2
x^2 - y^2

= (x + y)(x - y)
= x² - xy + xy - y²
= x² - y²

Answer: x² - y²

(x + y)(x - y)
= x*x + x*y - x*y - y*y
= x^2 + xy - xy - y^2
= x^2 - y^2

x² - xy + xy - y²
x² - y²

when you have a similar situation you have to consider only the negative part and u have to elevate both of the members to 2... so the answer is:
x^2 - y^2
Byeeeeeee By an Italian girl

x^2-y^2

(x+y)(x-y)
= x^2 -xy + xy -y^2
= x^2 - y^2
= (x-y)^2
Glad to help! ^__^

yeah everyone is right x square - y square

x(x-y)+y(x-y), which is:
x²-xy+yx-y² and that gives:
x²-y². This is an IDENTITY, so better learnt it ..........

(x + y)(x - y) = x^2 + xy - xy - y^2 = x^2 - y^2

x^2 - y^2

By the way, it is called Difference of Two Squares.