化簡...
(4^n+1 + 2^2n)/5=?
maths.................
2008-04-30 11:34 pm
回答 (2)
2008-04-30 11:54 pm
✔ 最佳答案
(4^n+1 + 2^2n)/5= (4^n+1 + 4^n)/5
= (4x4^n + 4^n)/5
= (4^n)(4+1)/5
= 4^n
2008-04-30 11:56 pm
我估你個問題係咁:
化簡[4^(n+1) + 2^(2n) ]/5......
首先4^(n+1) = 4(4^n)
其次, 2^(2n) = 4^n
所以[4^(n+1) + 2^(2n) ]/5
= [4(4^n)+4^n]/5
=[5(4^n)]/5
=4^n
化簡[4^(n+1) + 2^(2n) ]/5......
首先4^(n+1) = 4(4^n)
其次, 2^(2n) = 4^n
所以[4^(n+1) + 2^(2n) ]/5
= [4(4^n)+4^n]/5
=[5(4^n)]/5
=4^n
收錄日期: 2021-04-13 15:29:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080430000051KK01142