更新1:
PLS HELP!!
maths(方程式)
2008-04-30 5:29 am
1) Danny and Howard has a total amount of $800.If the sum of 1/4 of Danny's money and 1/3 of Howard's money is $220, how much money does each of them have?
回答 (3)
2008-04-30 5:37 am
✔ 最佳答案
D + H =800D=800-H
(1/4) D + (1/3)H = 220
3D+4H=2640
3(800-H)+4H=2640
2400 -3H +4H =2640
H=240
D=560
2008-04-29 21:38:23 補充：
Let D be the amount of Danny
and H be the amount of Howard
2008-05-05 4:21 am
Let Danny has $x
Then Howard has $(800-x)
x/4 + (800-x)/3 = 220
3x + 4(800-x) = 2640
3x + 3200-4x = 2640
560 = x
x = 560
∴ Danny has $560 and Howard has $240
Then Howard has $(800-x)
x/4 + (800-x)/3 = 220
3x + 4(800-x) = 2640
3x + 3200-4x = 2640
560 = x
x = 560
∴ Danny has $560 and Howard has $240
參考: 小女子 + 朋友 =]
2008-04-30 5:47 am
Let x be the amount of Danny's money
Let y be the amount of Howard's money
x+y=800---(1)
¼x+1/3y=220---(2)
(2)x3,
¾x+y=660---(3)
(1)-(3),
¼x=140
x=560
Sub x=560 into (1),
x+y=800
560+y=800
y=140
2008-04-29 21:53:38 補充：
錯誤補充:
Sub x=560 into (1),
x+y=800
560+y=800
y=240
Let y be the amount of Howard's money
x+y=800---(1)
¼x+1/3y=220---(2)
(2)x3,
¾x+y=660---(3)
(1)-(3),
¼x=140
x=560
Sub x=560 into (1),
x+y=800
560+y=800
y=140
2008-04-29 21:53:38 補充：
錯誤補充:
Sub x=560 into (1),
x+y=800
560+y=800
y=240
參考: me, me
收錄日期: 2021-04-20 20:49:24
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