factor 2x^2-32?
回答 (8)
✔ 最佳答案
2x²-32
=2(x²-16)
=2(x+4)(x-4)
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RE:
factor 2x^2-32?
2x^2 - 32
= 2(x^2 - 16)
= 2(x + 4)(x - 4)
2(x² - 16)
2(x - 4)(x + 4)
factorise 2x^2 - 32:
2 is a common factor, so take this outside the brackets:
2(x^2 - 16)
using the "difference of two squares" rule (one squared number minus another squared number), you can further simplify and factorise the expression:
= 2(x-4)(x+4)
...And that's it really! hope that makes sense..
2[(x^2) - 16 ] =0
ie x = +4, -4
收錄日期: 2021-05-01 10:25:49
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