factor 2x^2-32?

2x²-32

=2(x²-16)

=2(x+4)(x-4)

2x 2 32

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RE:
factor 2x^2-32?

2x^2 - 32
= 2(x^2 - 16)
= 2(x + 4)(x - 4)

2(x² - 16)
2(x - 4)(x + 4)

All of them are right

factorise 2x^2 - 32:

2 is a common factor, so take this outside the brackets:

2(x^2 - 16)

using the "difference of two squares" rule (one squared number minus another squared number), you can further simplify and factorise the expression:

= 2(x-4)(x+4)

...And that's it really! hope that makes sense..

2[(x^2) - 16 ] =0

ie x = +4, -4