When 2.86g of hydrated sodium carbonate Na2 CO3 ．nH2O is heated to
constant weight, the mass of the residue is 1.06g.
Determine the value of n.
CHEMMMMM` 10分
2008-04-28 8:54 am
回答 (1)
2008-04-28 9:18 am
✔ 最佳答案
In 2.86 g of Na2CO3•nH2O:Mass of Na2CO3 = 1.06 g
Mass of H2O = 2.86 - 1.06 = 1.8 g
Molar mass of Na2CO3 = 23x2 + 12 + 16x3 = 106 g mol-1
Molar mass of H2O = 1x2 + 16 = 18 g mol-1
Mole ratio Na2CO3 : H2O
= (1.06/106) : (1.8/18)
= 0.01 : 0.1
= 1 : 10
Hence, n = 10
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