factor 2x^2-8?

it is simple:
2(x^2-4)
2(x-2)(x+2)

therefore,
2x^2 = 8,
and
x^2 = 4.

if
x^2=4,
x = +/- 2

First, you factor out the 2 (GCF)
2(x^2-4)
Then, you find the difference of 2 squares using the formula:(x^2-y^2) = (x+y) (x-y)....so:
2(x+2)(x-2)
then ur done factoring :D

(2x-4) (x+2)

2(x-2)(x+2)

ok, im not positive but...
first do 2-8 which equals -6
so now u have 2x^-6 and that all depends on what x is. if u dont know what x is then that is the farthest you can go. hope this helps.

EDIT:
wow, looks like i was way off. lol. sorry about that.=D

2x^2 - 8
= 2(x^2 - 4)
= 2(x + 2)(x - 2)

2x^2-8

=2(x^2-4)

=2(x+2)(x-2)

2 (x² - 4)
2 (x - 2 ) (x + 2)

Hi,

For this question, we can see that there's a common factor of 2 in each of the presented terms. We can therefore factor that out of the expression to get:

2 ( x ^ 2 - 4 )

Now, x^2 - 4 can be factored as the difference of squares to get:

2 ( x - 2 ) ( x + 2 ) <=== FINAL ANSWER

I hope that helps you out! Please let me know if you have any other questions!