Ok. I'm stuck.... Simplify the product using the distributive property.
(5h-5) (5h-6)
The answer: 25h^2 - 55h + 30
(I'm not sure how to do the 2 on top of the 25h thing..)
Now how did I get that answer?
Math problems?
2008-04-27 4:35 pm
回答 (10)
2008-04-27 4:43 pm
✔ 最佳答案
FOIL = First, Outside, Inside, LastMultiply the First term of each polynomial:
5h∙5h = 25h²
Multiply the Outer terms:
5h∙(-6) = -30h
Multiply the Inner terms:
(-5)(5h) = -25h
Multiply the Last term of each polynomial:
(-5)(-6) = 30
Add the products together:
25h² -30h -25h +30 = 25h² -55h +30
2008-04-27 11:56 pm
you'd used the foil method. (5h-5)(5h-6)=multiply the first 5h to to 2nd 5h then same om 5h to -6.then multiply -5 to 2nd 5h and the same -5 to -6.u need to have an equation editor to put the exponent or fraction .if u have microsoft word, thenopen word,click insert,object,create new tab.in object type,scroll down to find microsoft equation3.0.(if not avail.,u have to download it).need more help?(microsoft office online:help and how to:insert an equation).print it and juct follw the direction.
2008-04-27 11:54 pm
i think you got it.
2008-04-27 11:47 pm
You have to multiply everything in the first parenthasis by everything in the second parenthasis.
5h*5h= 25h^2
5h*-6= -30h
-5*5h= -25h
-5*-6= 30
25h^2-30h-25h+30
combined like terms (-30h & -25h)
25h^2-55h+30 ta-da
5h*5h= 25h^2
5h*-6= -30h
-5*5h= -25h
-5*-6= 30
25h^2-30h-25h+30
combined like terms (-30h & -25h)
25h^2-55h+30 ta-da
2008-04-27 11:42 pm
When you use the distributive property, you multiply each term in the parenthesis by the terms in the other parenthesis. First, multiply 5h by 5h. You will get 5h^2. Multiply 5h by -6. You will get -30h. Multiply -5 by 5h. You will get -25h. Finally, multiply -5 by -6. You will get 30. Right now you should have 25h^2-30h-25h+30. You can combine -30h and -25h to simplify. Your finished result will be 25h^2-55h+30. I hope this helps! :)
2008-04-27 11:40 pm
Multiplly every thing in the 2nd bracket by every thing in the 1st bracket:
(5h - 5)(5h - 6)
= 5h(5h - 6) - 5(5h - 6)
= 25h^2 - 30h - 25h + 30
= 25h^2 - 55h + 30.
(5h - 5)(5h - 6)
= 5h(5h - 6) - 5(5h - 6)
= 25h^2 - 30h - 25h + 30
= 25h^2 - 55h + 30.
2008-04-27 11:40 pm
(5h-5) (5h-6)
you do
5h*5h+5h*-6-5*5h+5*6
25h^2 - 30h -25h+ 30
25h^2 - 55h + 30
you do
5h*5h+5h*-6-5*5h+5*6
25h^2 - 30h -25h+ 30
25h^2 - 55h + 30
2008-04-27 11:39 pm
Hello,
First you multiply first time by first term
First term by second term
Second term by first term
Second term by second term
Then you combine like terms.
Bye.
First you multiply first time by first term
First term by second term
Second term by first term
Second term by second term
Then you combine like terms.
Bye.
2008-04-27 11:39 pm
(5h - 5)(5h - 6)
= 5h*5h - 5*5h - 6*5h + 6*5
= 25h^2 - 25h - 30h + 30
= 25h^2 - 55h + 30
= 5h*5h - 5*5h - 6*5h + 6*5
= 25h^2 - 25h - 30h + 30
= 25h^2 - 55h + 30
2008-04-27 11:38 pm
Well you have to use the FOIL process:
What that means is First, Outside, Inside, and Last and you just multiply them together
1. (5h - 5)(5h - 6) first of each function
5h*5h = 25h^2
2. (5h - 5)(5h - 6) outside of each function
5h*(-6) = -30h
3. (5h - 5)(5h - 6) inside of each function
(-5)(5h) = -25h
4. (5h - 5)(5h - 6) last of each function
-5*-6= 30
now put them all together
25h^2 - 55h +30
:)
What that means is First, Outside, Inside, and Last and you just multiply them together
1. (5h - 5)(5h - 6) first of each function
5h*5h = 25h^2
2. (5h - 5)(5h - 6) outside of each function
5h*(-6) = -30h
3. (5h - 5)(5h - 6) inside of each function
(-5)(5h) = -25h
4. (5h - 5)(5h - 6) last of each function
-5*-6= 30
now put them all together
25h^2 - 55h +30
:)
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