4x-[7-2(x-1)]=x+11
要程序+答案
F.1 Maths
2008-04-27 5:09 pm
回答 (2)
2008-04-27 10:24 pm
✔ 最佳答案
4x-[7-2x+2]=x+114x-7+2x-2=x+11
6x-9=x+11
6x-x=11+9
5x=20
x=4
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2008-04-27 5:14 pm
4x-[7-2x+2]=x+11
4x-7+2x-2=x+11
6x-9=x+11
5x=20
x=4
小心d d+正負號ne~~
2008-04-27 09:15:28 補充：
計遲左tim= =
4x-7+2x-2=x+11
6x-9=x+11
5x=20
x=4
小心d d+正負號ne~~
2008-04-27 09:15:28 補充：
計遲左tim= =
收錄日期: 2021-04-13 15:29:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080427000051KK00613