10d)
y = cos^2 (\theta) - sin (\theta) +1
ans: 0<=y<=9/4
17)
cos^2 (\theta) -6cos(\theta) + p=0
find range of p
ans: -7<=p<=5
問題係,我點知square之後既minimum係0定係(本身既min)^2
更新1:
再加 如果有個condition係 min(u)
更新2:
find uv 既range, min(u)min(v)
更新3:
θ既min?唔係-∞<θ<+∞咩？