how can I solve?

2008-04-26 7:01 am
(3X-1)^2 - (1-2X)^2 - (5X+8)(x-3) = 4

回答 (9)

2008-04-26 7:10 am
✔ 最佳答案
(3x - 1)² - (1 - 2x)² - (5x + 8)(x - 3) = 4
9x² - 6x + 1 - (1 - 4x + 4x²) - (5x² - 7x - 24) = 4
9x² - 6x + 1 - 1 + 4x - 4x² - 5x² + 7x + 24 = 4
arranging the equation from the highest exponent to the lowest
9x² - 4x² - 5x² - 6x + 4x + 7x + 1 - 1 + 24 = 4
0 + 5x + 24 = 4
5x = -24 + 4
5x = -20
x = -4
2008-04-26 5:57 pm
(3x - 1)^2 - (1 - 2x)^2 - (5x + 8)(x - 3) = 4
(3x - 1)(3x - 1) - (1 - 2x)(1 - 2x) - (5x^2 + 8x - 15x - 24) = 4
9x^2 - 6x + 1 - (1 - 2x - 2x + 4x^2) - 5x^2 - 8x + 15x + 24 - 4 = 0
9x^2 - 6x + 1 - 1 + 4x - 4x^2 - 5x^2 + 7x + 20 = 0
9x^2 - 9x^2 - 6x + 4x + 7x + 1 - 1 + 20 = 0
5x + 20 = 0
5x = -20
x = -20/5
x = -4
2008-04-26 2:59 pm
(3x - 1)² = ________9x² - 6x + 1
- (1 - 2x)² = _____- 4x² + 4x - 1
-(5x + 8)(x - 3) = _- 5x² + 7x + 24
SUM = 5x + 24

5x + 24 = 4
5x = - 20
x = - 4
2008-04-26 2:20 pm
first distribute and multiply everything so you get
(9x^2-6x+1) - (1-4x+4x^2) - (5x^2-7x-24)

now add/ subtract like numbers

(9x^2 - 4x^2 - 5x^2) + (-6x + 4x +7x) + (1 -1 +24)
0 + 5x + 24 = 4
5x = -20
x = -4

^^ hope this helped
2008-04-26 2:14 pm
i got x=-4 as well... the first guy had the second equation expanded wrongly...
2008-04-26 2:09 pm
use a TI-30.... or better one.... of the texas instrument calculators... or the calculator on your pc...
2008-04-26 2:08 pm
expand and solve.

(9x^2 -6x +1) - (4x^2 - 4x +1) - (5x^2 - 7x - 24) = 4

-5x +24 = 4

-5x = -20

x = 4
2008-04-26 2:06 pm
graph it on your calculator
2008-04-26 2:05 pm
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