I need to solve each equation for the indicated variable (leave +- in your answers) I cant figure these two out. Thanks
1) (x-4)^2 = 49
2) x^2 =-12
Algebra help please? Struggling?
2008-04-25 7:44 pm
回答 (5)
2008-04-25 7:53 pm
✔ 最佳答案
(x - 4)² = 49Take sqrt of both sides
x - 4 = ±7
x = ±7 + 4
x = 11 or x = -3
~~~~~~~~~~~~~~~~~~~~
x² = -12
Take sqrt of both sides
x = ±√(-12)
x = ±2i√3 (complex roots)
參考: MG
2008-04-25 7:50 pm
x-4 = +/- 7
x = 11 or -3
x = sqrt(-12) = +/-2 sqrt(-3) = no real solution
or +/- 2sqrt(3)i (if you have done complex number)
x = 11 or -3
x = sqrt(-12) = +/-2 sqrt(-3) = no real solution
or +/- 2sqrt(3)i (if you have done complex number)
2008-04-25 7:55 pm
1,
x=11 or x=-3
2,
x = â(-12) = ±2i â3 = APPROX 3.46i
x=11 or x=-3
2,
x = â(-12) = ±2i â3 = APPROX 3.46i
2008-04-25 7:50 pm
(1) (x - 4) ^2 = 49
sqrt((x - 4) ^2) = sqrt(49)
x - 4 = +7 or - 7
x = 11 or x = -3
(2) x ^2 = -12
x = 12i
x = 3 + 2i or 3 - 2i
sqrt((x - 4) ^2) = sqrt(49)
x - 4 = +7 or - 7
x = 11 or x = -3
(2) x ^2 = -12
x = 12i
x = 3 + 2i or 3 - 2i
2008-04-25 7:49 pm
(x-4)^2=49 take the sqrt of both sides
x-4=7 or x-4= -7
x=11 or x=-3
x^2= -12 again, sqrt both sides
x=2*sqrt(3i)....i think
x-4=7 or x-4= -7
x=11 or x=-3
x^2= -12 again, sqrt both sides
x=2*sqrt(3i)....i think
收錄日期: 2021-05-02 14:46:46
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