solve for p ?
回答 (5)
2008-04-25 3:56 pm
✔ 最佳答案
3/8 (P-4) - 1/2 (3p + 2)= 1/4 (9p-7)LCM of the denominators
LCM(8,2,4) = 8
Multiply through by 8 (clearing out the denominators)
3(p-4) - 4(3p+2) = 2(9p-7)
3p - 12 - 12p - 8 = 18p - 14
3p - 12p - 18p = 12 + 8 - 14
-27p = 6
p = -6/27 = -2/9
參考: MG
2008-04-25 10:59 pm
3(p - 4)/8 - 1(3p + 2)/2 = 1(9p - 7)/4
(3p - 12)/8 - (3p + 2)/2 = (9p - 7)/4
8[(3p - 12)/8 - (3p + 2)/2] = 8[(9p - 7)/4]
3p - 12 - 4(3p + 2) = 2(9p - 7)
3p - 12 - 12p - 8 = 18p - 14
3p - 12p - 18p = 12 - 14 + 8
-27p = 6
p = 6/-27
p = -2/9
(3p - 12)/8 - (3p + 2)/2 = (9p - 7)/4
8[(3p - 12)/8 - (3p + 2)/2] = 8[(9p - 7)/4]
3p - 12 - 4(3p + 2) = 2(9p - 7)
3p - 12 - 12p - 8 = 18p - 14
3p - 12p - 18p = 12 - 14 + 8
-27p = 6
p = 6/-27
p = -2/9
2008-04-25 10:57 pm
multiply by 8:
3(p - 4) - 4(3p+2) = 2(9p - 7)
3p - 12 - 12p - 8 = 18p - 14
-9p - 20 = 18p - 14
-27p = 6
p = -6/27 = -2/9
3(p - 4) - 4(3p+2) = 2(9p - 7)
3p - 12 - 12p - 8 = 18p - 14
-9p - 20 = 18p - 14
-27p = 6
p = -6/27 = -2/9
2008-04-25 10:55 pm
3p - 12 - 12p - 8 = 18p - 14
- 27 p = 6
p = - 2 / 9
- 27 p = 6
p = - 2 / 9
2008-04-25 10:55 pm
3/8 (P-4) - 1/2 (3p + 2)= 1/4 (9p-7)
Let's start this by multiplying everything by 8 to remove the fractions:
3(P - 4) - 4(3p + 2) = 2(9p - 7)
Now we'll simplify the expressions, and move all the p's to one side and the P and the constants to the other:
3P - 12 - 12p - 8 = 18p - 14
3P - 6 = 6p
(3P - 6) / 6 = p
or
(P/2) - 1 = p
Let's start this by multiplying everything by 8 to remove the fractions:
3(P - 4) - 4(3p + 2) = 2(9p - 7)
Now we'll simplify the expressions, and move all the p's to one side and the P and the constants to the other:
3P - 12 - 12p - 8 = 18p - 14
3P - 6 = 6p
(3P - 6) / 6 = p
or
(P/2) - 1 = p
收錄日期: 2021-05-01 10:25:26
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