✔ 最佳答案
Since I assume this is for homework, I will tell you how to do a similar problem using the method I would use, instead of giving you the answer.
Let's use the system
1) 6x+5y=8
2) 4x-2y=2
Since each is an equation, you can manipulate a single equation on its own and still maintain equality. The key to a system such as this is to eliminate all variables but one. The way to do that is to find the lowest common multiple of the coefficient of the variable you are trying to eliminate. In my system let's eliminate x. Find the lowest common multiple of 4 and 6. It's 12. So you multiply both sides of equation 1 by 2 leaving you with the modified yet still equal equation 12x+10y=16
Multiply equation 2 by 3 so that your modified equation is 12x-6y=6
Then it's basically a subtraction problem of equations.
(12x+10y=16)
-(12x-6y=6)
-----------------------
0x +16y = 10
Thus, y= 10/16=5/8
Then to solve for y, just plug the number that was just solved for back into either original equation.
4x-2(5/8)=2
4x-5/4=2
4x=13/4
x=13/16
As a sanity check, plug both numbers into the other unused equation to see if the equality still holds.
6*(13/16) +5*(5/8)=8
39/8+25/8=8
64/8=8
8=8 (see, it worked!)
That's the basic method for solving these systems of equations.