81(x+1/3)^2=1 solve for x?

81(x+1/3)² = 1 ----- taking square root
9(x + 1/3) = ± 1
Let = +1
9x + 3 = 1
9x = – 2
x = – 2/9
Let = – 1
9x + 3 = –1
9x = – 4
x = – 4/9
x = –2/9 or – 4/9
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(x + 1/3)² = 1/81
(x + 1/3) = ± (1/9)
x = (-1/3) ± (1/9)
x = - 2/9 , x = - 4/9

=81(x+1/3)^2=1
(rooting both sides)
=9(x+1/3)=1
=9x+3=1
=9x=-2
=x=-2/9

x=-2/9

81[(x + 1)/3]^2 = 1
[(x + 1)/3]^2 = 1/81
(x + 1)/3 = ±√1/81
(x + 3)/3 = ±1/9

(x + 3)/3 = 1/9
x + 3 = 1/3
x = 1/3 - 3
x = -2 2/3

(x + 3)/3 = -1/9
x + 3 = -1/3
x = -1/3 - 3
x = -3 1/3

∴ x = -2 2/3 , -3 1/3

81(x+1/3)^2=1
(x+1/3)^2=1/81

x+1/3=1/9 or x+1/3= -1/9
Thus, x = -2/9 or x=-4/9