can some one please help me factor this compleatly
I would also be very nice if some one did this too
-6a^2 - 11a + 2
m^2 - 7m + 12?
2008-04-23 5:47 am
回答 (11)
2008-04-23 5:51 am
✔ 最佳答案
m^2 - 7m + 12 = (m - 3)(m - 4).-6a^2 - 11 + 2 = (-a - 2)(6a - 1).
-John
2008-04-24 9:20 am
Question 1
(m - 4)(m - 3)
Question 2
(- 6a + 1)(a + 2)
(m - 4)(m - 3)
Question 2
(- 6a + 1)(a + 2)
2008-04-23 12:34 pm
1)
m^2 - 7m + 12
= (m - 4)(m - 3)
2)
-6a^2 - 11a + 2
= (-6a + 1)(a + 2)
m^2 - 7m + 12
= (m - 4)(m - 3)
2)
-6a^2 - 11a + 2
= (-6a + 1)(a + 2)
2008-04-23 5:56 am
m^2 - 7m + 12
= (m - 4)(m + 3)
-6a^2 - 11a + 2
= (-6a + 1)(a + 2)
= (m - 4)(m + 3)
-6a^2 - 11a + 2
= (-6a + 1)(a + 2)
2008-04-23 5:54 am
m^2 - 7m + 12 = (m - 4)(m - 3)
2008-04-23 5:53 am
(m - 4) (m - 3)
(6a - 1) (-a - 2)
(6a - 1) (-a - 2)
2008-04-23 5:53 am
What two number multiply to get 12 and add to get -7? -4 and -3.
(m-3)(m-4)
-6a^2 - 11a + 2
Multiply everything by -1 to get out the negative on the 6.
6a^2+11a-2
Since the coefficient in front of a^2 is not one, you have to mix it up a bit. It becomes more of a guess and check.
(6a-1)(a+2)
(m-3)(m-4)
-6a^2 - 11a + 2
Multiply everything by -1 to get out the negative on the 6.
6a^2+11a-2
Since the coefficient in front of a^2 is not one, you have to mix it up a bit. It becomes more of a guess and check.
(6a-1)(a+2)
2008-04-23 5:52 am
the answer for the first one is (m-4)(m-3)
the answer for the second one is (-a-2)(6a -1)
the answer for the second one is (-a-2)(6a -1)
2008-04-23 5:51 am
(m-3)(m-4)
(-6a+1)(a+2)
(-6a+1)(a+2)
2008-04-23 5:51 am
m² - 7m + 12
(m - 4)(m + 3)
-6a² - 11a + 2
(-6a + 1)(a + 2)
(m - 4)(m + 3)
-6a² - 11a + 2
(-6a + 1)(a + 2)
收錄日期: 2021-05-01 10:24:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080422214723AAuTk8Y