maths!!!!!

The long division is even not necessary since the quotient of dividing f(x) by (x - 2) is not needed here:
f(x) = (x + 1)(x3 - 3x + 5) + 4
When f(x) is divided by x - 2, the remainder is f(2):
f(2) = (2 + 1)(23 - 6 + 5) + 4 = 21

2008-04-22 11:17:29 補充：
Sorry, f(2) should be 25

2008-04-22 22:51:09 補充：
From the given, we have:
f(x) = (x^2 - 3x + 5)(x + 1) + 4
So when f(x) is divided by x-2, the remainder is:
f(2) = (2^2 - 6 + 5)(2 + 1) + 4
= 13

f(x) = (x+1)(x^3 - 3x + 5) + 4
= x^4 + x^3 - 3x^2 + 2x + 9
By using long division
= (x- 2) (x^3 + 3x^2 +3x+8) + 25
Remainder is 25