更新1:
不是很明 可以詳細點 thx
A maths ............
回答 (2)
2008-04-24 12:32 am
✔ 最佳答案
tan x = m, 180<x<270Then x is in quadrant III and sin x < 0 and cos x < 0
tan x = (sin x / cos x )
m = (-m/k) / (-1/k)
where k = sqrt(m^2 + 1)
sin x = - m / sqrt(m^2 + 1)
2008-04-20 4:38 am
if tan x = m , where 180<X<270,express the value of sinx in trms of m
Solution:
∵180<X<270
∴x in quadrant III
sinx=m/√(m+1)
=m√(m+1)/(m+1)
Solution:
∵180<X<270
∴x in quadrant III
sinx=m/√(m+1)
=m√(m+1)/(m+1)
收錄日期: 2021-04-23 20:36:33
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