A maths ............

tan x = m, 180<x<270
Then x is in quadrant III and sin x < 0 and cos x < 0
tan x = (sin x / cos x )
m = (-m/k) / (-1/k)
where k = sqrt(m^2 + 1)
sin x = - m / sqrt(m^2 + 1)

if tan x = m , where 180<X<270,express the value of sinx in trms of m
Solution:
∵180<X<270
∴x in quadrant III

sinx=m/√(m+1)
=m√(m+1)/(m+1)