4x^2+12x=55?

4x^2 + 12x = 55

Subtract 55 from both sides
4x^2 + 12x - 55 = 0

Factor the polynomial
(2x - 5)(2x + 11) = 0

Set both factors equal to 0
2x - 5 = 0
2x + 11 = 0

Solve for x
2x = 5
2x = -11

The answer is
x = 5/2
x = -11/2

4x² + 12x - 55 = 0
x = [ - 12 ± √ (144 + 880 ) ] / 8
x = [ - 12 ± √ (1,024 ) ] / 8
x = [ - 12 ± 32 ] / 8
x = 20 / 8 , x = - 44 / 8
x = 5 / 2 , x = - 11 / 2

4x^2 + 12x = 55
4x^2 + 12x - 55 = 0
(2x + 11)(2x - 5) = 0

2x + 11 = 0
2x = -11
x = -11/2
x = -5 1/2 (-5.5)

2x - 5 = 0
2x = 5
x = 5/2
x = 2 1/2 (2.5)

∴ x = -5 1/2 (-5.5) , 2 1/2 (2.5)

4x^2+12x=55
4x^2+12x-55=0
(2x-5)(2x+11)=0

so 2x-5=0 and 2x+11=0
are solutions

2x-5=0, x=5/2
2x+11=0, x= -11/2

x+1)(x-1) = 8
x^2 - 1 = 8
x^2 = 9
x = 3

ezz question

bring 55 to the left side
4x^2+12x-55=0
factor it
use zero product principle n ur done
(2x-5)(2x+11)
x=5/2 or x=-11/2

4x^2+12x-55=0
(2x-5)(2x+11)=0
2x-5=0 x=5/2
2x+11=0 x=-11/2