1. Solve the equation 2sin^2@ + 7sin@ + 3 = 0, where 0 =/< @ =/< 360.
2. Let f(x)=x^3+kx^2-kx+4, where k is a constant. If f(x) is divisible by x-2, find the remainder when f(x) is divided by x-4.
I suspect that the answers provided are wrong, so I'm posting the questions here. Thanks!!! :)
Two CE Maths questions
2008-04-18 8:14 pm
回答 (1)
2008-04-18 8:50 pm
✔ 最佳答案
1) 2 sin2 @ + 7 sin @ + 3 = 0 ( 2 sin @ + 1 )( sin @ + 3 ) = 0
sin @ = - 1 / 2 or sin @ = -3 ( rejected )
@ = 210* or 330*
2) Given that f ( 2 ) = 0,
23 + k ( 2 )2 - k ( 2 ) + 4 = 0
2k = -12
k = -6
f ( x ) = x3 - 2x2 + 2x + 4
f ( 4 ) = 43 - 6 ( 4 )2 + 6 ( 4 ) + 4 = -4
2008-04-18 12:51:50 補充：
Typing error: f ( x ) = x^3 - 6x^2 + 6x + 4
參考: My Maths Knowledge
收錄日期: 2021-04-13 15:27:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080418000051KK00780