solve the simultaneous equations?

y = 11x + 3

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y = 4x^2
11x + 3 = 4x^2
4x^2 - 11x - 3 = 0
(4x - 1)(x + 3) = 0

4x - 1 = 0
4x = 1
x = 1/4 (0.25)

x + 3 = 0
x = -3

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y = 11x + 3
y = 11(1/4) + 3
y = 11/4 + 3
y = 3 11/4
y = 5 3/4 (5.75)

y = 11x + 3
y = 11(-3) + 3
y = -33 + 3
y = -30

∴ (0.25 , 5.75) , (-3 , -30)

4x² - 11x - 3 = 0
(4x + 1)(x - 3) = 0
x = -1/4 , x = 3
y = 1/4 , y = 36

(-1/4 , 1/4) , (3 , 36)

y=11x + 3 (1)
y =4x^2 (2)
if both = y then:
4x^2 = 11x + 3
4x^2 -11x - 3 = 0
(4x +1)(3x - 3) = 0
so either 4x + 1 = 0 giving 4x = -1 giving x = -1/4
or (x - 3) = 0 giving x = 3
if x is -1/4 then substituting into (2)
y = 4(-1/4)^2 = 1/4
if x = 3 then substituting into (2)
y = 4(3)^2 = 36
so solution is (-1/4,1/4) or (3,36)

y = 11x + 3
and y = 4x^2
So
11x + 3 = 4x^2
4x^2 - 11x - 3 = 0
4x^2 - 12x + x - 3 = 0
4x(x - 3) + 1(x - 3) = 0
(x - 3)(4x + 1) = 0
So
x = 3 or x = -1/4
So
y = 36 or y = 1/2

y = 11x + 3
y = 4x²

Plug the second equation in for y in the first equation:

4x² = 11x + 3
4x² - 11x - 3 = 0
factor:
(4x + 1)(x - 3) = 0
set each term equal to 0:
4x + 1 = 0
4x = -1
x = -1/4
and
x - 3 = 0
x = 3

Therefore we have two possible x values: -1/4 and 3..
Plugging those values in for x in either equation yields the following ordered pairs:

(-1/4, 1/4)
(3, 36)

y = 11x + 3
y = 4x^2

as y = 4x^2 you can substitute this value of y into the first equation to give:
4x^2 = 11x + 3
This is then a quadratic:
4x^2 - 11x - 3 = 0
You can factorise this to:
(4x + 1) (x - 3)
so x = 3 , -1/4

When x = 3
y = 11x + 3
y = 36

When x = -1/4
y = 11x + 3
y = 1/4

Overall:
x = 3
y = 36


x = -1/4
y = 1/4

Hope this helps

y=11x+3
y=4x^2

Make them equal.
11x+3 = 4x^2
4x^2 - 11x - 3 = 0
After using the quadratic equation, we get:
x = { 11 ± Sq Root ( 121 + 48 ) } ÷ 8
x = 3 or -0.25

So, if x = 3, y=11x+3
y = 11(3) + 3
y = 36

And, if x = -0.25, y=11x+3
y = 11(-0.25)+3
y = 0.25

Hence,
x=3
y=36

OR

x=-0.25
y=0.25

First you have to put it in equation and u get
4x^2= 11x+3

Move everything to one side
4x^2-11x-3= 0

Factorise it
(4x+1) (x-3) =0
therefore x= 3 and -1/4
Then y= 36 and 1/4