How do I solve the inequality 3x + 5 _< 16?
回答 (6)
2008-04-15 4:21 pm
✔ 最佳答案
3x+5<163x< 16-5
3x<11
x<11/3
2008-04-15 4:38 pm
3x + 5 <= 16
3x <= 16 -5
3x <= 11
x <= 11/3
x <= 3.6666
If we were to graph it on a number line you would draw a SOLID dot at 11/3 and make the arrow go left towards infinity.
In coordinate form it would be
(- infinity, 11/3 ]
Brackets are used when x actually touches the point.
(when it is equal to)
3x <= 16 -5
3x <= 11
x <= 11/3
x <= 3.6666
If we were to graph it on a number line you would draw a SOLID dot at 11/3 and make the arrow go left towards infinity.
In coordinate form it would be
(- infinity, 11/3 ]
Brackets are used when x actually touches the point.
(when it is equal to)
2008-04-15 4:27 pm
3x+5=16 (Treat _< as =)
3x=11(16-5)
x=11/3
3x=11(16-5)
x=11/3
2008-04-15 4:23 pm
3x + 5 ≦ 16
3x ≦ 16 - 5
3x ≦ 11
x ≦ 11/3
x ≦ 3 2/3
3x ≦ 16 - 5
3x ≦ 11
x ≦ 11/3
x ≦ 3 2/3
2008-04-15 4:21 pm
3x + 5 < 16
3x +5 -5 < 16 -5
3x < 11
3x/3 < 11/3
x < 11/3
i don't know what the _ was supposed to be
3x +5 -5 < 16 -5
3x < 11
3x/3 < 11/3
x < 11/3
i don't know what the _ was supposed to be
2008-04-15 4:20 pm
3x<=11
x<=11/3
x<=11/3
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