How do I solve the inequality 3x + 5 _< 16?

3x+5<16
3x< 16-5
3x<11
x<11/3

3x + 5 <= 16

3x <= 16 -5

3x <= 11

x <= 11/3

x <= 3.6666

If we were to graph it on a number line you would draw a SOLID dot at 11/3 and make the arrow go left towards infinity.

In coordinate form it would be
(- infinity, 11/3 ]

Brackets are used when x actually touches the point.
(when it is equal to)

3x+5=16 (Treat _< as =)
3x=11(16-5)
x=11/3

3x + 5 ≦ 16
3x ≦ 16 - 5
3x ≦ 11
x ≦ 11/3
x ≦ 3 2/3

3x + 5 < 16
3x +5 -5 < 16 -5
3x < 11
3x/3 < 11/3
x < 11/3
i don't know what the _ was supposed to be

3x<=11
x<=11/3