the sum of 3 consecuative odd integers is 279. what are the integers?

2x + 1 + 2x + 3 + 2x + 5 = 279
6x = 270
x = 45

91 , 93 , 95 are required odd integers.

Let x smallest integer
x + 2 next larger
x + 4 largest
x + x + 2 + x + 4 = 279
3x + 6 = 279
3x = 273
x = 91
91 93 and 95

x + (x + 2) + (x + 4) = 279
3x + 6 = 279
3x = 273
x = 91

91,93,95

91 + 93 + 95
= 279

x+x+2+x+4=279
3x=273
x=91
x+2=93
x+4=95

91, 93, 95, i did my work on a sheet of paper cant do math on a computer

x+(x+2)+(x+4)=279
3x+6=279
3x=273
x=91

x+2=93

x+4=95

I break down the statement and think logically:
3 integers, consecutive, added together make a value
3 is odd, so the center number can be found by dividing the total by 3
calculate 279/3=93
1 odd integer above = 95
1 odd integer below =91
check work, 91+93+95=279
work checks as correct.

I'm not saying this method or the others is more or less appropriate, but since my approach seems different I thought I would share.

Because they're odd the equation will be:

x + x+2 + x+4 = 279

3x + 6 = 279
3x = 273
x = 91

So the integers are 91 + 93 + 95 = 279