silicon(IV) oxide問題!!!

silicon(IV) oxide 的 (IV) ，是它的 redox number
單一個 O 的 redox number 是 -2。兩個 O ，即係兩個 -2。
因為 SiO2 是穩定的，所以 Si + O2 = 0 ，
所以 Si = 0 - O2
= - [(-2)*2]
= +4

所以 Si 是 +4

所以 silicon(IV) 有 4個 bond


至於，點解會係 SiO2，你可以試下用密鋪平面的方法(暫時當它是一個平面，其實是一個立體)，如果以 SiO2 及 SiO4 做基本單位，睇下邊一個可以鋪出一個平面。

Silicon(IV) oxide is also named as silicon dioxide. It has giant covalent structure, in which a huge number of Si atoms and a huge number of O atoms are joined together by strong covalent bonds to form a network.

It is true that each Si atom is covalently bonded to 4 O atoms, but don’t miss that each O atom is covalently bonded to 2 Si atoms.

Since it is a network structure, there are no molecules. Therefore, it is represented by empirical formula. Since the mole ratio of Si atom to O atom in the network structure is 1 to 2, its empirical formula is SiO2.