Phy 練習中2條諗唔通- - F4

2008-04-13 12:22 am
6)Alex is climbing rock.If the power of his muscle cannot ve greater than 30Wand his mass is 65 kg, what is his maximum speed of climbing up the rock surfaces?

8)A lift system has a 120-kg lift cage and its power is 15kW. Find the maximum number of people who can be raised at 2ms-1. Assume that the mass of each person is 70 kg and the lift system has no power loss.

回答 (3)

2008-04-13 1:43 am
✔ 最佳答案
6.打中文ok??唔ok都要ok =v="
咁speed係m/s啦...即係每秒移動幾快啦...
而Power又係指每秒產生ge energy...
兩者ge單位都係xx per 1s..就可以mix埋黎計..
p=power...e=energy...t=time...每秒都係30w..即係每秒provide30J
P=E/t
E=30J per s
30=(1/2)mv^2
60=65v^2
v=0.960769
v=0.961ms^-1
his maximum speed of climbing up the rock surfaces is 0.961ms^-1
8.呢個ge work done係垂直..即係mgh
the energy is needed for raised at 2ms-1...
P=E/t
15x1000=mgh per s/t(per s)
15000w=m x10x2
m=750kg
the maximum number of people :(750-120)/70=9
so the maximum number of people who can be raised at 2ms^-1 is 9 people
有唔明再問~

2008-04-12 23:11:42 補充:
too easy 只不過我估唔到佢垂直咁爬 =口=
P=E/t
30=mgh/(per s)
30=650h
h=0.0462m per s
so the velocity 係0.0462ms^-1...垂直向上...
我見到rock surfaces仲以為佢打斜...甚至打橫..即係bb仔咁爬..
sorry呀 ^^"

2008-04-12 23:29:36 補充:
呀...原來物理愛好者—R 已經答咗..非常感謝你的幫忙~
2008-04-13 3:27 am
-0-我知道了
P=E/t
30=work done by muscles /time
30=Gain in PE /time
30=(65)(10)(h)/time
v=0.0462 ms-1

這裡E=30J per s,應是E=30Js
2008-04-13 3:09 am
HEYHEY!!!第6條既答案係 0.0462ms-1 bo,我一開始都係用你個方法計...但都係計你依個答案-0-


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