how do you factorise when dealing with brackets? (2x+7)^2 +3(2x+7)+2?

(2x+9) ( 2x+8)

Just let u = 2x + 7.

Then your equation is:
u^2 + 3u + 2
= (u + 2)(u + 1)
= ((2x+7) + 2)((2x+7) + 1)
= (2x + 9)(2x + 8)

4x^2+28x+49+6x+21+2
= 4x^2+34x+72
= (2x+9)(2x+8)


first simplify th brackets.... and add......

[ (2x + 7) + 2 ] [ (2x + 7) + 1
( 2x + 9) (2x + 8)

OR

Let y = 2x + 7
y² + 3y + 2
(y + 2)(y + 1)
(2x + 9)(2x + 8)

all you really need to do is simplify the problem by getting all the like numbers together, i think it's 10x+72

(2x+7)^2 +3(2x+7)+2=
(2x+7)^2 +(2x+7)+2(2x+7)+2=
(2x+7)((2x+7)+1) + 2(2x+7+1)=
(2x+7+1)(2x+7+2)=
(2x+8)(2x+9)

(2x + 7)^2 + 3(2x + 7) + 2
= (2x + 7)(2x + 7) + 6x + 21 + 2
= 4x^2 + 14x + 14x + 49 + 6x + 23
= 4x^2 + 28x + 6x + 49 + 23
= 4x^2 + 34x + 72
= 2(2x^2 + 17x + 36)
= 2(2x + 9)(x + 4)

word that you could ingredient out a similar value from both words: (-2x^2yz) this can leave you with: (-2x^2yz) * (a million + 16y^2) the different solutions did not get the unfavorable astounding! once you ingredient out the unfavorable from both words, they'll both become effective words. ------------------------------------- further information: both Iceman and woman were given it incorrect.

To factorize a complex question, you have to first put it in its simplest form.

First you get rid of the brackets by expanding them. Also, (2x+7)^2 is the same as (2x+7)(2x+7). the ^2 is just a way of simplifying.

(2x+7)^2 +3(2x+7)+2


= (2x+7)(2x+7) + 3(2x+7) + 2
= 4x^2 + 14x + 49 + 6x + 21 + 2

Then you collect all the 'like terms'. So you put all the x^2 terms together, all the x terms together and all the normal numbers together.

= 4x^2 + 20x + 72

Now that it's in its simplest form you can factorize. The greatest factor of all three terms is 4, so that number will be in front of the bracket. (The greatest factor of all terms always goes in front of the bracket). Then you can put the other factor of the term in the bracket. So your final answer is:

4(x^2 + 5x + 18)

= 4x^2 + 20x + 72 which was simplified from:

=(2x+7)^2 +3(2x+7)+2


Does that answer your question?

I think you would just make it

2x^2 + 6x+21+2 (general form)
8x^3 + 23 (simplest form)