1) 2開方5/3+開方60 (Simplify the following expressions)
2) 開方6/2/5 (Express the following surds in their simplest forms)
3) 開方2(4開方2+開方8) (Simplify the following expressions)
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中二數學問題!(好急架!)
2008-04-12 5:16 am
回答 (2)
2008-04-12 6:49 am
✔ 最佳答案
12√(5/3)+√60
=(2√3)(√5)/3+(√12)(√5)
=(√5)[2√3/3+2(√3)]
=(√5)[(8/3)(√3)]
=8√15/3
2
√6/2/5
=√(32/5)
=√160/5
=4√10/5
3
√2(4√2+√8)
=√2(4√2+2√2)
=√2(6√2)
=6*2
=12
2008-04-11 22:50:20 補充：
第二條是不是６又５分之２？
2008-04-13 9:30 pm
(1)
2x√(5/3) +√60
=2√(5/3)+√(2x2x3x3x5/3)
=2√(5/3)+6√(5/3)
=8√(5/3)
(2)
√6/2
------- ...............(1)
√5
√6
------...................(2)
√2/5
是(1)還是(2)
如果是(1)
√6/2
-------
√5
=√[6/(2x5)]
=√(3/5)
如果是(2)
√6
-----
√2/5
=√[6/(2/5)]
=√[(6x5)/2]
=√15
(3)
√2(4√2+√8)
=4(√2x√2)+√(2x2x2)x√2
=4x2+√(2x2x2x2)
=8+2x2
=8+4
=12
2x√(5/3) +√60
=2√(5/3)+√(2x2x3x3x5/3)
=2√(5/3)+6√(5/3)
=8√(5/3)
(2)
√6/2
------- ...............(1)
√5
√6
------...................(2)
√2/5
是(1)還是(2)
如果是(1)
√6/2
-------
√5
=√[6/(2x5)]
=√(3/5)
如果是(2)
√6
-----
√2/5
=√[6/(2/5)]
=√[(6x5)/2]
=√15
(3)
√2(4√2+√8)
=4(√2x√2)+√(2x2x2)x√2
=4x2+√(2x2x2x2)
=8+2x2
=8+4
=12
收錄日期: 2021-04-26 13:06:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080411000051KK02400