a math

2008-04-11 3:59 am
Find the area of the quadrilateral with vertices(0,2),(4,0),(3,3)and(-1,0)

回答 (3)

2008-04-11 4:08 am
✔ 最佳答案
Area
=(1/2)[(3*2+0*0+-1*0+4*3)-(3*0+2*-1+0*4+0*3]
=10//
2008-04-11 11:50 am
In anti-clockwise direction, the vertices are (0,2),(-1,0),(4,0),(3,3),(0,2)
Area of the quadrilateral
= 1/2 [0*0+(-1)*0+4*3+3*2-(-1)*2-4*0-3*0-0*3]
=1/2 (20)
=10
2008-04-11 4:33 am
Solution:

First, you should join (-1,0) and (0,2) . Next, join (0,2) and (3,3) . Last, join (3,3) and (4,0). After you have joined these lines, you will be able to see two triangles and a trapezium. Calculate each of the polygon and add them to together will done this calculation.


圖片參考:http://www.freewebtown.com/dennistang/knowledge/images/math.png

From the above, 1 represents area of the triangle on the second quadrant, the rest are the polygons on the first quadrant.

The area is the sum of those three numbers shown, i.e.

1.5 7.5 1

Since that, the area is equal to 1.5 7.5 1.
i.e. Area = 1.5 7.5 1
= 10 cm2


收錄日期: 2021-04-13 15:25:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080410000051KK02192

檢視 Wayback Machine 備份