MATH FACTOR THEOREM

2008-04-09 2:50 am
factorize P(x), using factor theorem
P(x) = x^3 - 4x^2 -4x -5

P(x) = x^3 -7x^2 + 7x -6

P(x) = x^3-4x+15

3題,THX

回答 (1)

2008-04-09 3:06 am
✔ 最佳答案
1.
P(x)=x^3-4x^2-4x-5
可試x=1,-1,5,-5
最後試到
P(5)=125-100-20-5=0
x-5 is a factor
by division, 
P(x)=(x-5)(x^2+x+1)
(x^2+x+1)cannot be factorized
(b^2-4ac<0)
P(x)=(x-5)(x^2+x+1)

2.
P(x)=x^3-7x^2+7x-6
可試x=1,-1,2,-2,3,-3,6,-6
最後試到
P(6)=216-252+42-6=0
x-6 is a factor
by division, 
P(x)=(x-6)(x^2-x+1)
(x^2-x+1)cannot be factorized
(b^2-4ac<0)
P(x)=(x-6)(x^2-x+1)


3.
P(x)=x^3-4x+15
可試x=1,-1,3,-3,5,-5,15,-15
最後試到
P(-3)=-27+12+15=0
x+3 is a factor
by division, 
P(x)=(x+3)(x^2-3x+5)
(x^2-3x+5)cannot be factorized
(b^2-4ac<0)
P(x)=(x+3)(x^2-3x+5)


收錄日期: 2021-04-16 23:15:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080408000051KK01970

檢視 Wayback Machine 備份