cosθ 係咩呀 ???

2008-04-07 10:35 pm
If (m,n) is a point on th unt circle x^2 + y^2 = z, and θ is an angle in standard position whose trminal ray goes through (m,n). How do I find cosθ ??

Thank you~

回答 (1)

2008-04-08 8:12 am
✔ 最佳答案
The length of the hypotenuse = √(m^2+n^2)

cosθ
= The length of the horizontal/The length of the hypotenuse
=m/√(m^2+n^2)

2008-04-08 00:13:04 補充:
其實這裡的length of the horizontal可正可負,不過既然用了符號m就不用考慮這麼多了


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