化籍 1-(sin@-cos@)^2 / tan@
列式 ****************************
三角恆等式 請幫忙 10分
2008-04-06 8:38 pm
回答 (2)
2008-04-06 8:53 pm
✔ 最佳答案
1-(sin@-cos@)2 / tan@=1-(sin2@+cos2@-2sin@cos@) /tan@
=1-(1-2sin@cos@) /tan@
=2sin@cos@ /tan@
=2cos2@
2008-04-06 8:54 pm
(1-(sin@-cos@)^2 / tan@)
=(1-sin@^2+sin@cos@-cos@^2)/tan@
=(cos@^2-cos@^2+sin@cos@)/tan@
=sin@cos@ x cos@/sin@
=cos@^2
=(1-sin@^2+sin@cos@-cos@^2)/tan@
=(cos@^2-cos@^2+sin@cos@)/tan@
=sin@cos@ x cos@/sin@
=cos@^2
收錄日期: 2021-04-21 13:34:44
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080406000051KK01049