MATHS!!!!!!!

(a) By the Remainder Theorem, let f(x) = x10 - 1 and then when f(x) is divided by x - 1, the remainder will be f(1) = 0.
(b) From the results of (a), we sub x = 11, then:
When 1110 - 1 is divided by 11 - 1, the remainder is zero.
Therefore, 1110 - 1 is divisible by 10.
Also by long division, we can find out that the quotient when x10 - 1 is divided by x - 1 will be x9 + x8 + x7 + x6 + x5 + x4 + x3 + x2 + x + 1 and sub x = 11, the quotient will have its unit digit equal to 0 since from 1 to x9 (total 11 terms), each term will have its unit digit equal to 1 for x = 11.
Finally, x9 + x8 + x7 + x6 + x5 + x4 + x3 + x2 + x + 1 is divisible by 10 and x10 - 1 is divisible by 100.

a. x^9+x^8+x^7+x^6+x^5+x^4+x^3+x^2+x+1
b唔識