24^2+0.8AC^2=AC^2
我列了一條畢氏定理的式, 但不懂怎樣把AC的值計出來, 請寫出步驟和詳細解釋, 謝謝!
ｆ２數學一題（好簡單）１０分～
2008-04-05 3:07 am
回答 (3)
2008-04-05 4:28 am
✔ 最佳答案
24^2+0.8AC^2=AC^2so
AC^2-0.8AC^2=24^2
II
0.2AC^2=576
II
AC^2=2880
so
AC= 53.6656 (四捨五入)
Hope I can help you!!!
參考: my brain
2008-04-06 5:59 am
Are you want to write: 24^2+(0.8AC)^2=AC^2
24^2+(0.8AC)^2=AC^2
576+(0.8AC)^2=AC^2
576=AC^2-(0.8AC)^2
576=0.2AC
AC=576/0.2
AC=2880
Is it your answer???
2008-04-05 22:03:58 補充：
AC^2=2880
AC=53.66563146...
AC=53.67(correct to 3 sig. fig)
24^2+(0.8AC)^2=AC^2
576+(0.8AC)^2=AC^2
576=AC^2-(0.8AC)^2
576=0.2AC
AC=576/0.2
AC=2880
Is it your answer???
2008-04-05 22:03:58 補充：
AC^2=2880
AC=53.66563146...
AC=53.67(correct to 3 sig. fig)
參考: Me
2008-04-05 3:22 am
24^2+0.8AC^2=AC^2
AC^2-0.8AC^2=24^2
0.2AC^2=24^2
0.2AC^2=576
AC^2=2880
AC=53.7 ( correct to 3 sig. fig.)
AC^2-0.8AC^2=24^2
0.2AC^2=24^2
0.2AC^2=576
AC^2=2880
AC=53.7 ( correct to 3 sig. fig.)
參考: Hope i can help you
收錄日期: 2021-04-13 15:24:48
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