ｅ點數係點計架我諗來諗去都諗唔到
更新1:
Let x = (m-1) . 設 x = (m-1) 。 16(m-1)^2 - 8(m-1) +1 = 16(x)^2 - 8x +1 = (4x-1)^2<~~~~點樣可以去到ｅ度． = [4(m-1) -1]^2 = (4m-5)^2
factorization~~~~
回答 (3)
2008-04-04 7:35 pm
✔ 最佳答案
16(m-1)^2 - 8(m-1) 1= 16(x)^2 - 8x 1
= (4x)^2 - 2(4x) 1－－其實你要的步驟，就是將數字轉換一下，應用「(a - b)^2 = a^2 - 2ab b^2」。因為16=4^2，8=2(4)(1)，你也記得任何數都何乘無限個1吧？一般直接看出來便可以因式分解，不會寫出簡化了的這一步。
=( 4x -1 )^2
= [4(m-1) -1]^2
= (4m-5)^2 //
2008-04-04 6:55 pm
16(m-1)^2-8(m-1)+1
= [4^2(m-1)^2]-(8m-8)+1
= [4(m-1)]^2-2(4m-4)+1
= (4m-4)^2-2(4m-4)+1
= [(4m-4)-1]^2
= (4m-5)^2
ok?
= [4^2(m-1)^2]-(8m-8)+1
= [4(m-1)]^2-2(4m-4)+1
= (4m-4)^2-2(4m-4)+1
= [(4m-4)-1]^2
= (4m-5)^2
ok?
2008-04-04 6:52 pm
Let x = (m-1) .
設 x = (m-1) 。
16(m-1)^2 - 8(m-1) +1
= 16(x)^2 - 8x +1
= (4x-1)^2
= [4(m-1) -1]^2
= (4m-5)^2
設 x = (m-1) 。
16(m-1)^2 - 8(m-1) +1
= 16(x)^2 - 8x +1
= (4x-1)^2
= [4(m-1) -1]^2
= (4m-5)^2
參考: myself
收錄日期: 2021-04-20 22:17:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080404000051KK00598