64-x^3
can someone show mw how?
how do you factor a binomial?
2008-04-03 3:50 pm
回答 (5)
2008-04-03 3:56 pm
✔ 最佳答案
64-x^3this is a difference of 2 cubes
64 = 4³
and x³ obvioulsy = x³
to factor the difference of 2 cubes, apply the following formula:
a³-b³ = (a-b)(a²+ab+b²)
a = 4
b = x
64 - x³ = (4 - x)(16 + 4x + x²) <--final answer
2008-04-03 10:57 pm
That's not a binomial.
Cube factorization.
a^3 + b^3 = (a+b) (a^2 - ab + b^2)
a^3 - b^3 = (a-b) (a^2 + ab + b^2)
Cube factorization.
a^3 + b^3 = (a+b) (a^2 - ab + b^2)
a^3 - b^3 = (a-b) (a^2 + ab + b^2)
2008-04-03 10:55 pm
This is the difference of two cubes:
The rule here is:
a³ - b³ = (a - b)(a² + ab + b²)
So 64 - x³ factors out to:
(4 - x)(16 + 4x + x²)
The rule here is:
a³ - b³ = (a - b)(a² + ab + b²)
So 64 - x³ factors out to:
(4 - x)(16 + 4x + x²)
2008-04-03 10:54 pm
64-x^3
= 4^3 - x^3
= (4-x)(4^2+4x+x^2)
= (4-x)(16+4x+x^2)
= 4^3 - x^3
= (4-x)(4^2+4x+x^2)
= (4-x)(16+4x+x^2)
2008-04-03 10:54 pm
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
64 - x^3
= (4 - x)(16 + 4x + x^2)
64 - x^3
= (4 - x)(16 + 4x + x^2)
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