how to solve 27x³ + 8 / 3x + 2?

(27x³+8) / (3x+2)
= ((3x)³ + 2³) / (3x+2)
= (3x+2)((3x)² - (3x)2 + 2²) / (3x+2)
= 9x² - 6x + 4

= (27x³ + 8)/(3x + 2)
= 9x² - 6x + 4

Answer: 9x² - 6x + 4

(27x^3 + 8)/(3x + 2)
= (3x + 2)(9x^2 - 6x + 4)/(3x + 2)
= 9x^2 - 6x + 4

27x^3+8=(3x)^3+2^3
applying identity (a+b)^3=a^3+b^3+3ab(a+b),
((3x+2)^3-18x(3x+2))/3x+2
=(3x+2)^2-18x
=9x^2+12x+4-18x
=9x^2-6x+4

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27•x³ + 8
------------
3•x + 2
~~~~~~~~
9•x•x•x + 4
---------------
x
~~~~~~~
Answer: 9x^2+4