How do I solve 2(3x + 5) -1= 10x +1?

6x + 9 = 10x + 1
8 = 4x
x = 2

2(3x + 5) -1= 10x +1

First transfer the 2 on the left side through:

6x + 10 - 1 = 10x + 1
combine like terms on the left side:
6x + 9 = 10x + 1
subtract 9 from both sides:
6x = 10x - 8
subtract 10x from both sides:
-4x = -8
divide both sides by -4:
x = 2

10x^2-23x+12=0 sum=-23 product=a hundred and twenty splitting the midsection term such that the sum=-23 and the product is a hundred and twenty, -23=(-15)+(-8) and a hundred and twenty=(-15)(-8 10x^2-15x-8x+12=0 getting rid of the person-friendly ingredient 5x(2x-3)-4(2x-3)=0 (2x-3)(5x-4)=0 if the productis 0 each and every productcan be 0 equation 2x-3=0 2x=3 or x=3/2 5x-4=0 5x=4 or x=4/5 so the solutionset={3/2,4/5)

2(3x + 5) - 1 = 10x + 1
2*3x + 2*5 - 1 = 10x + 1
6x + 10 - 1 = 10x + 1
6x - 10x = -10 + 1 + 1
-4x = -9 + 1
-4x = -8
x = -8/-4
x = 8/4
x = 2

Lets solve the Left hand side of the equation
2 (3x+5)-1
becomes
2(3x) + 2 (5) -1 ( Distributive property)
6x + 10 -1
and further becomes
6x +9
Now the given equation is reduced to
6x + 9 = 10x +1
(transferring like terms)
9 - 1 = 10x - 6x
8 = 4x
x = 2

2(3x + 5) - 1 = 10x + 1

add the 1 from the left to the 1 on the right.

2(3x + 5) = 10x + 2

divide everything by two

3x + 5 = 5x + 1

subtract 3x from 5x

5 = 2x + 1

subtract on from 5

4 = 2x

divide by 2

2 = x

2(3x + 5) -1= 10x +1
6x+10-1=10x+1
6x-10x+9=1
-4x=1-9
-4x=-8
x=-8/-4
x=2

2(3x + 5) -1= 10x +1

6x + 10 -1 = 10x + 1
10 - 1 -1=10x - 6x
8=4x
8/4=x

x=2

2(3x+5) - 1 = 10x + 1
Firstly u have to expand something here.
6x + 10 - 1 = 10x + 1
Now do whatever u can do here in this step.
6x + 9 = 10x + 1
You see.Both sides have terms with "x" so what do u do?Do this.
9 - 1 = 10x - 6x
Again do what u can in this step.
8 = 4x
Using your logic you will know that 4 multiplied by something gives u 8.Only 2 is acceptable because 8/4 = 2.
2 = x
x = 2 (to make it look better).